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Statistics is a good subject in the Class 10 syllabus, bringing together the power of numbers, data interpretation, and the beauty of mathematical precision. For students aiming to excel in their mathematics exams, working through Statistics Class 10 Important Questions and understanding the theories can make a big difference in the learning of the subject. These extra questions cover concepts of data, measures of central tendency, cumulative frequency, graphical representation, and more, enabling students to build analytical skills essential not only for exams but also for real-life data interpretation.
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Sol. c) 30 is the upper limit of the median class
Explanation:
∴ N/2
= 45/2
=22.5; that lies in the interval 20-30
So, the median class is 20-30 and the upper limit of the median class is 30.
Find the value of x and also find the mean expenditure:
Sol. Total number of families= 200
N=200
172+X = 200
X = 200-172
X=28
Mean Expenditure= fixi / fi
Mean Expenditure= 532500 / 200
Mean Expenditure= 2662.5
Sol. b) 25
Explanation:
∴ N/2
= 66/2
=33
As per the cumulative frequency chart, 33 is somewhat close to 37.
∴ the average class size is between 10 and 15.
The lower limit of the median class =10.
In the given data, the maximum frequency is 20, which falls in the class of 15-20.
∴ , the modal class's lower limit is set to 15.
The sum of the lowest limit of the modal class and median class = 10 + 15 =25.
As a result, 25 is the result of adding the median class and modal class lower limits.
Sol. Median = 7.5 and Mode = 6.3
Use the empirical relationship between mean, median, and mode
Mean - Mode = 3(Mean - Median)
Mean - 6.3 = 3(Mean - 7.5)
Mean - 6.3 = 3 Mean - 22.5
- 6.3 + 22.5 = 3 Mean - Mean
16.2 = 2 Mean
Mean = 8.1
The median class and modal class may differ based on data distribution. For example, if the frequencies have been changed so that the highest frequency resides in a different class, the two classes may not coincide. We determine that the median and modal classes of grouped data can be alike depending on the distribution of the data.
Sol.
76+x+y = 100
x+y = 100-76
⇒ x+y = 24 …(1)
To find cumulative frequency:
N/2= 1000/2 = 500 falls mainly in 400-500 interval
Where lower limit l = 500 ,
class difference h =100,
cumulative frequency c.f = 36+x
Median = l + ((n/2-cf))/f)xh
Median = 500 + ((50 - (36+x))/20 x 100
525 = 500 + ((50 - (36+x))/20 x 100
525 = 500 + (14 + x)x 5
525 = 500 + (70 + 5x)
525 = 570 + 5x
5x = 570 - 525
5x = 45
x = 9
Putting x=9 in eq 1
9+y = 24
y = 24 - 9
y= 15
12, 15, 22, 44, 44, 48, 50, 51
Sol. a) only mean
Explanation:
An outlier is a data point that differs significantly from other observations of a data set.
Data set = 12, 15, 22, 44, 44, 48, 50, 51
Median = (44+44)/2
= (88)/2
= 44
Mean= (12+ 15+ 22+ 44+ 44+ 48+ 50+ 51)/8
= 236/8
= 35.75
Mode = 44
The median might be affected slightly, but not as much as the mean. The mode would likely remain unchanged unless the outlier becomes the most frequent value.
Sol. Mean temperature of the city for 31 days = 35.7°C
Mean temperature of first 8 days = 28.4°C
Mean temperature of next 12 days = 36.4°C
We know,
Mean = Sum of all observations/ Number of observations
Therefore, we get:
Sum of temperatures of all the 31 days = 35.7 × 31
= 1106.7°C
Sum of temperatures of first 8 days = 28.4 × 8
= 227.2°C
Sum of temperatures of the next 12 days= 36.4×12
= 436.8°C
The number of remaining days= 31-8-12
= 11 days
Then, the sum of temperatures of 11 days = 1106.7 - 227.2 - 436.8
= 442.7°C.
Hence, the mean temperature of 11 days= 442.711
= 40.2°C
Sol. Given,The mean score of the class = 60
alf of the students scored 80 marks or above.
Dipti said, "Each of the remaining half of the students would definitely have 40 marks or below in the test for the mean to be 60 marks".
We know,
Mean = Sum of all observations/Number of observations
Therefore, we have:
For example,
Consider the number of students in the class = 105 students got 80 marks or above.
Let the marks be: 80, 90, 85, 95, 80, 40, 50, 20, 30, 30
Thus, the mean mark= (80+90+85+95+80+40+50+20+30+30)/10
= 6000
= 60 marks.
Here, 5 students got 80 and above and the remaining 5 students got the marks as: 40, 50, 20, 30, 30.That is, one of them from the remaining half got 50 marks, which is above 40 marks as Dipti stated.Hence, Dipti's statement is wrong.
(Source of data: https://ourworldindata.org/mental-health.)
Can the median of the above data be more significant than 12.5%? Give a valid reason.
Sol. Median = l + ((n/2-cf))/f)xh
Here, n/2 = 42/2 = 21, which falls under the range 10-12.5.
Then, l = 10, h = 2.5, cf = 11, and f = 25.
The median cannot be greater than 12.5% because the median class is between 10-12.5%.
Let us find the median of the above data.
Therefore, we get:
Median = 10 + ((21 - 11)/25) × 2.5
= 10 + ((21 - 11)/25) × 2.5
= 10 + ((10)/25) × 2.5
= 10+1
= 11%, which is less than 12.5%.
Hence, it is proved that the median of the given data cannot be greater than 12.5%.
Which of the following is the modal class?
Sol. b) 2-3
To determine the modal class, one has to find the class interval displaying the maximum frequency of gamers. The maximum frequency is 24, relating to the class interval 2–3.
The purpose of statistics class 10 extra questions is to strengthen students’ knowledge of critical concepts, helping them handle different types of questions that may appear in the exams. By practicing these questions, students develop the ability to apply statistical formulas and interpret data, enhancing both accuracy and speed.
A solid understanding of core statistical measures like mean, median, and mode is essential for Class 10 students. Most statistics problems rely on these concepts, which also frequently appear in extra and important questions.
The mean, defined as the average of a data set, provides a measure of central tendency. Students in Class 10 are taught various methods to determine the mean, such as
Understanding these methods and when to use each one is important for students as they approach statistics class 10th extra questions.
Median: The median is the middle value of an ordered data set, providing insight into data distribution. It is especially useful for understanding data sets. Students must be adept at organising data and applying the formula for cumulative frequency to find the median accurately.
Mode: The mode is the most frequently occurring value in a data set. When dealing with categorical data, it's particularly helpful to identify the most common data points in a distribution. In practice, the mode can provide immediate insights into trends within data, making it a valuable measure of central tendency for statistical analysis.
A frequency distribution table organizes data into classes and shows the frequency of each class, simplifying large data sets for easier interpretation. Students in class 10 learn how to construct these tables, which is an essential skill when addressing important statistics questions that involve data handling.
Cumulative frequency is a progressive summing of frequencies, allowing students to understand data distribution over intervals. This concept is essential for calculating percentiles, medians, and quartiles—all of which provide additional layers of insight into the data.
A visual representation of data helps understand trends and patterns at a glance. Students in Class 10 are taught various types of graphical representation, such as:
The ability to interpret and create these graphs is essential for effectively addressing the extra questions in class 10 statistics.
Although not directly related to statistics, we introduce probability concepts in tandem, providing students with a preliminary understanding of chance events. These ideas are crucial for students as they prepare for more advanced studies in probability and statistics.
Statistical literacy allows students to make informed decisions based on data in everyday situations. For instance, understanding the mean helps in determining average marks, while median and mode are relevant in analyzing income levels or demographic data.
Many students find statistics challenging due to its nature and the need for logical reasoning. Extra questions, especially those designated as statistics class 10 imp questions, require critical thinking and a step-by-step approach to solve.
Extra questions often push students to go beyond rote learning and apply statistical methods creatively. Here are some tips:
By practicing statistics with 10 important questions, students gain confidence and enhance their problem-solving abilities. This targeted practice can help them perform well in exams, especially in questions involving complex data interpretations.
Exams frequently cover certain topics within statistics that have high-scoring potential. Important questions in Statistics Class 10th often involve calculating the mean, median, or mode for grouped data, drawing frequency polygons, and constructing cumulative frequency tables. These topics are crucial for scoring well.
Here are some proven strategies to help students maximize their scores:
By working through the statistics class's 10 extra questions, students improve their understanding of statistical principles and sharpen the skills necessary for handling exam questions with confidence. This subject not only prepares students for exams but also equips them with skills that will be useful in higher studies and daily life. Focusing on statistics in class 10 and developing a strong understanding of data analysis can lead to opportunities in various fields.