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Carbon and its compounds are an essential part of the Class 10 Science curriculum. Carbon is a unique element that forms the basis for numerous organic compounds, making it important for life and many industries. Chapter 4 of the Class 10 Science textbook covers important topics like how carbon forms bonds, its different forms (like diamond and graphite), and the reactions of carbon compounds.
If you want to top the class 10 science exam, then focusing on Class 10 Carbon And Its Compounds Important Questions is essential. These questions often appear in exams and can boost your confidence.
PREMIUM EDUCART QUESTIONS
(Most Important Questions of this Chapter from our 📕)
In the table below, we have provided the links to Class 10 Science Chapter 4 Most Important Questions downloadable PDFs. Now you can download them without requiring a login.
Answer:
This compound does not follow the general formula of alkanes (CnH2n+2), meaning it is not saturated. C3H4 is an unsaturated hydrocarbon. Specifically, it could either be an alkyne (with one triple bond) or a diene (with two double bonds).
(i) What is true about the type of flame this compound will give on combustion?
Unsaturated hydrocarbons, such as C3H4, tend to produce a yellow sooty flame on combustion.
(ii) Draw all the possible straight chain structures of this compound.
Propyne (CH≡C−CH3CH)
and Propadiene (CH2=C=CH2)
Answer:
Kohli can identify hexene and hexyne using the bromine water test because they are unsaturated hydrocarbons that react with bromine water, decolorizing it. However, hexane cannot be identified because it does not react and does not affect the color of bromine water
Answer:
(a) Which name has she written incorrectly? Justify your answer.
Methanone is incorrect because a ketone requires at least three carbon atoms, and no compound with one carbon can be named "methanone."
(b) What name should she have written instead?
She should have written propanone (CH3COCH3), the first member of the homologous series of ketones.
Answer:
(a) Name the functional groups of the MAIN organic compounds present in wine and vinegar.
The main organic compound in wine is ethanol (CH3CH2OH), and the functional group is –OH (hydroxyl group).
The main organic compound in vinegar is acetic acid (CH3COOH), and the functional group is –COOH (carboxyl group)
(b) Based on the atoms getting added/removed when wine is converted to vinegar, name the type of reaction that happens.
This is an oxidation reaction, as oxygen is added, and the alcohol is converted to a carboxylic acid.
(c) Name any chemical reagent that would be used for the same reaction if it is carried out in the laboratory.
In the laboratory, the oxidation of ethanol to acetic acid can be carried out using potassium permanganate (KMnO4) or acidified potassium dichromate (K2Cr2O7) as the oxidizing agent. Both reagents supply oxygen for the oxidation process.
Answer:
(a) What is the chemical formula for ethanol?
The chemical formula of ethanol is C2H5OH.
(b) What other compound is obtained as a by-product when ethanol is obtained from a sugar?
When ethanol is produced from sugars during fermentation, carbon dioxide (CO2) is obtained as a by-product.
(c) What would be the products formed when ethanol undergoes complete combustion? Support your answer with a balanced chemical equation.
When ethanol undergoes complete combustion, the products formed are carbon dioxide (CO2) and water (H2O).
The balanced chemical equation is:
C2H5OH+3O2→2CO2+3H2O
This reaction releases energy in the form of heat and is used as a source of renewable energy.
Answer:
The property of carbon atoms that is instrumental in the formation of polythene is catenation. In the case of polythene production, the double bonds in ethene (CH2=CH2) break under high pressure and temperature, allowing the carbon atoms to link together in long chains.This process, called addition polymerization, results in the formation of polythene, a polymer with a repeating unit of −CH2−CH2−
Answer:
No, an alkane and an alcohol cannot be isomers. They do not share the same molecular formula. The presence of the −OH group in alcohols alters the hydrogen count and makes them distinct from alkanes.
Answer:
The molecular formula of the alkane is C₁₁H₂₀, indicating it contains 11 carbon atoms and 20 hydrogen atoms. In this compound, each carbon atom is tetravalent, forming single covalent bonds with two adjacent carbon atoms and two hydrogen atoms. The hydrogen atoms are arranged around the carbon atoms in a tetrahedral geometry, which ensures the most stable configuration for carbon's four bonds.
Answer:
(a) Write the names of the carboxylic acid and the alcohol from which this compound is formed.
Carboxylic Acid: Propanoic acid (CH₃-CH₂-COOH)
Alcohol: Ethanol (CH₃-CH₂-OH)
(b) Apart from mixing the carboxylic acid and the alcohol, what should be done to form this compound?
The reaction proceeds as follows:
CH₃-CH₂-COOH (Propanoic acid) + CH₃-CH₂-OH (Ethanol) → CH₃-CH₂-COO-CH₂-CH₃ (Ethyl propanoate) + H₂O
This process produces ethyl propanoate and water as the byproduct.
Answer:
When 2-butanol reacts with concentrated sulfuric acid, it undergoes a dehydration reaction, producing two possible alkenes: 2-butene and 1-butene.
2-butene: CH3CH=CHCH3
1-butene: CH3CH2CH=CH2
in these reactions, concentrated sulfuric acid serves as a dehydrating agent, facilitating the removal of a water molecule from 2-butanol. This dehydration process leads to the formation of the corresponding alkenes, either 2-butene or 1-butene, depending on the elimination pathway.
Carbon, represented by the symbol 'C,' is an element in the periodic table due to its ability to form a large number of compounds. This is because carbon atoms can form four bonds with other atoms (called tetravalency) and connect to themselves in long chains (a property called catenation). These features make carbon central to many areas of science and everyday life.
In Class 10 Science Chapter 4 syllabus, you’ll learn about several aspects of carbon chemistry, including:
Focusing on carbon and its compounds in class 10 important questions helps you learn the key ideas in Chapter 4. Here’s how they can benefit you:
Knowing why class 10 carbon and its compounds are important questions is great, but how can you use them effectively? Here are some tips:
Carbon and its compounds are a major part of the Class 10 Science syllabus, and understanding this chapter is important for doing well in the exams. By practicing carbon and its compounds in class 10 important questions, you can be sure you're covering the most important topic and improve your chances of scoring high marks.
These questions not only prepare you for the exam but also improve your understanding of the concepts, which is crucial for further studies as well.