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Light is a fascinating phenomenon that plays an important role in our everyday lives. Chapter 9, Light Reflection and Refraction, introduces you to the basic properties of light and how it interacts with surfaces and mediums. The chapter covers all important concepts, such as the laws of reflection and refraction, ray diagrams for mirrors and lenses, and the applications of optical phenomena in devices like periscopes, telescopes, and cameras.
Here’s an expanded blog to know this chapter—in and out—and prepare effectively for your exams, along with a list of Important Questions of Light Class 10 to practice.
PREMIUM EDUCART QUESTIONS
(Most Important Questions of this Chapter from our 📕)
In the table below, we have provided the links to downloadable Light: Reflection And Refraction Class 10 Important Questions With Answers PDFs. Now you can download them without requiring a login.
Answer:
(a) P is equal to 4.5 D
Explanation:
P=P1+P2
P= 1/f
For lens P= 2D
For lens Q= 2.5D
P=P1+P2
=2+2.5
=4.5D
Answer:
(c) nm is more than na
Explanation:
When a ray of light enters a medium from air and bends towards the normal, it indicates that the speed of light is reduced in the medium. This happens because the refractive index of the medium (nm) is greater than the refractive index of air (na).
nasini=nmsinr
Answer:
(d) focal length
Explanation:
The paper is placed at the point where the sunrays converge after reflection from the mirror. This point is called the principal focus (F) of the mirror, and the distance between the mirror and this point is the focal length.
Answer:
(a) real and diminished
Explanation:
The image formed on the paper is real because the sunrays physically converge to form the image. Real images can be projected onto a surface like paper.
The image of the Sun formed by the spherical mirror is diminished because the Sun is at a very large distance (essentially at infinity), and the image at the focal point is a small bright dot representing the concentrated rays.
Answer:
(c) between pole and principal focus
Explanation:
When the object is between the pole and the principal focus, the reflected rays appear to diverge. If extended backward, they seem to originate from a point behind the mirror.
This creates a virtual, upright, and enlarged image, which can only be observed in this object position for a concave mirror.
Answer:
(c) rear-view mirror
Explanation:
The experiment mentioned likely involves a convex mirror or a concave mirror, depending on the context. Let’s analyze each option based on the typical uses of these spherical mirrors:
The mirror used in the experiment cannot be used as a rear-view mirror, as it would typically require a convex mirror, which is not used for focusing experiments like solar cookers or headlights.
Thus, "rear-view mirror" is NOT a common use for the type of spherical mirror likely used in this experiment.
Answer:
If the eyeball of a person has become slightly larger, the increased size causes the retina to move farther from the eye's lens. As a result, the light rays converge in front of the retina rather than directly on it. This condition is known as myopia or nearsightedness.
To correct myopia, the person should wear a lens that diverges the light rays slightly before they enter the eye, ensuring they focus properly on the retina.
Correct Lens:
This lens spreads the incoming light rays so that the eye's lens focuses them farther back, directly onto the retina, restoring clear vision.
Answer:
(a)
When Diana is looking at the Moon, the Moon is essentially at infinity. For an object at infinity, the light rays entering the eye are parallel, and they converge at the retina.
The focal length (f) of the eye's optical system must match the distance between the lens and the retina to form a sharp image:
f=17mm
=0.017m
(b)
When Diana is reading a book at a distance of u=20 cm=0.2 m, the image is formed at the retina, so the image distance (v) is 17 mm (0.017 m).
1/f= 1/v-1/u
1/f= 1/0.017 - 1/-0.2
1/f= 58.82+5
=63.82
f= 1/63.82
≈0.0157m=15.7mm
(c)
When Diana brings the book closer, the distance between the book and her eyes (uuu) becomes smaller. For the eye to focus on such a close object, the focal length of the eye's lens system must decrease further. However, the eye's ciliary muscles have a limit to how much they can adjust the lens shape. If the required adjustment exceeds this limit:
This inability to adjust sufficiently is why the letters become blurry.
Answer:
M= Height of image/Height of object
M= v/u
v= ½ . (-2)
v= −1m
The negative sign indicates that the image is virtual and behind the mirror.
1/f= 1/v - 1/u
1/f= -1 + ½
1/f= -½
f= -2m
Answer:
a. The power of the corrective lens is negative (−5.0 D), indicating it is a diverging lens. Diverging lenses are used to correct myopia (nearsightedness).
In myopia, the person can see nearby objects clearly but struggles to see distant objects. This occurs because the eye's lens focuses the image in front of the retina instead of on it. The diverging lens shifts the focal point back onto the retina, correcting the defect.
b. The relationship between the power PPP (in diopters) and the focal length fff (in meters) is:
P= 1/f
Substitute P=−5.0 D:
f= 1/(-5.0)
= −0.2m(or -20 cm)
Answer:
When a parallel beam of white light passes through a convex lens, the phenomenon of chromatic aberration causes light of different colors (wavelengths) to refract by different amounts. This occurs because the refractive index of the lens material varies with the wavelength of light—a phenomenon known as dispersion.
Shorter wavelengths (violet): Light with shorter wavelengths, such as violet, experiences a higher refractive index. This means violet light bends more sharply and converges closer to the lens.
Longer wavelengths (red): Light with longer wavelengths, such as red, has a lower refractive index. This means red light bends less sharply and converges farther from the lens.
The light of violet color will converge at a point closest to the lens because it has the shortest wavelength in the visible spectrum and is refracted the most by the lens. This behavior is consistent with the dispersive nature of the lens material, leading to chromatic aberration.
As an essential phenomenon, light exhibits unique behaviors like reflection and refraction when interacting with surfaces and media. Understanding these concepts is important for mastering the chapter Light: Reflection and Refraction.
Reflection of Light - Reflection occurs when light rays strike a surface and bounce back into the same medium. This phenomenon sticks to the fundamental laws of reflection:
Laws of Reflection:
Types of Reflection:
Regular Reflection:
Refraction of Light - Refraction is the bending of light when it passes from one medium to another with different densities. Key topics include:
Laws of Refraction:
Refractive Index:
Critical Angle and Total Internal Reflection (TIR):
Ray Diagrams and Optical Devices / Ray Diagrams for Spherical Mirrors:
Ray Diagrams for Lenses:
The principles of reflection and refraction form the foundation of numerous technologies and are integral to various scientific advancements. Here's a detailed look at their real-world applications:
Reflection and refraction are at the heart of many optical instruments used in science and day-to-day life:
Optical Fibers: Total Internal Reflection (TIR) enables optical fibers to transmit data as light signals with minimal loss. It is widely used in internet cables, medical endoscopes, and telecommunication networks for efficient and high-speed data transfer.
Telescopes: Reflecting and refracting telescopes rely on mirrors and lenses to magnify and observe distant celestial bodies. Large astronomical telescopes use parabolic mirrors for high-precision reflection, capturing faint light from stars and galaxies.
Virtual Reality (VR) and Augmented Reality (AR): Devices use reflection and refraction principles for immersive visual experiences by projecting light at precise angles.
Laser Applications: Refraction focuses laser beams for cutting, surgery, or scientific experiments, while reflection ensures device beam direction.
Master the Laws and Definitions
Practice Ray Diagrams
Focus on Applications
Revise and Practice Regularly
Clarify Doubts
Chapter 9 Light CBSE Class 10 bridges theoretical knowledge with practical applications, making it an important topic for exams and daily life. You can confidently tackle any question in this chapter by understanding the key concepts, mastering ray diagrams, solving Light Reflection And Refraction Class 10 Extra Questions and numerical problems, and revising applications.
Stay consistent in your preparation and keep practicing to shine bright, just like light!