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An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?
Resistance (R1) of an electric lamp = 100Ω
Resistance (R2) of of toaster = 50Ω
Resistance (R3) of water filter = 500Ω
A potential difference of the source (V) = 220V
The resistors are connected in series.
Total resistance in electric iron
1/R= 1/R1 + 1/R2 + 1/R3
1/R = 1/100 + 1/50 + 1/500
1/R = (5+10+1)/500
R = 500/16 Ω
R = 31.25 Ω
As per Ohm's law
R = V/I
31.25 Ω = 220 V/I
I = 220 V X 100 / 3125
I = 7.04 A
Resistance is 31.25 Ω and current is 7.04 A.
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