Chapter 11

NCERT
Class 10
Science
Solutions
10. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?

Question:

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4Ω, 0.5Ω and 12Ω, respectively. How much current would flow through the 12Ωresistor?

Answer:

Battery voltage: 9V

Resistors (series)=

R1=0.2Ω R2=0.3Ω R3=0.4Ω R4=0.5Ω R5=12Ω

Net Resistance Rnet= R1+R2+R3+R4+R5

Rnet= (0.2+0.3+0.4+0.5+12)Ω

Rnet=13.4Ω

As per ohm's law

V = IR

9V = IX13.4Ω

I= 9V/13.4Ω

I= 0.671A

0.671A current passes through 12Ω.

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