To Download PDF
Please verify your Whatsapp number first,
so you can download this pdf immediately
![](https://cdn.prod.website-files.com/5f5cf462f0ee5f4a999616bb/6597ba4553aab5ce1cf16062_1211.webp)
An object of size 7.0 cm is placed at a distance of 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a clear focused image of the object is formed? Find the size and nature of an object.
Height of an object h1 = 5 cm
Object distance u = – 27 cm
Focal length = – 18 cm
Height of an image h1 = ?
Image distance u = ?
From the formula :
⇒ 1/u + 1/v = 1/f
⇒ 1/(-27) + 1/v = 1/(-18)
⇒ 1/v = 1/18 + 1/27
⇒ - (3+2)/ 54
⇒ -1/54
⇒ v = –54 cm
Therefore, screen should be placed at a distance of 54 cm from the screen.
m = h2/h1 = - v/u
⇒ h2/7 = -54/-27
⇒ h2/7 = 2
⇒ h2 = 14 cm
Thus, the height of the image formed is 14 cm and is real and inverted in nature.
CBSE Class 10 Sample PapersMaths StandardMaths BasicHindi AHindi BSocial ScienceScienceSanskritEnglish
Please verify your Whatsapp number first,
so you can download this pdf immediately
Please type a valid 10 digit whatsapp number
OTP sent, check your whatsapp
Your OTP is incorrect, Please enter valid OTP