.avif){kind=small}
To Download PDF
Please verify your Whatsapp number first,
so you can download this pdf immediately
Send OTP
.svg)
A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower, when is the splash heard at the top? Given g = 10 ms–2 and speed of sound = 340 ms–1.
Case-I, u = 0, s = 500 m, g = 10 m/s2
∴ s = ut + 1/2 gt2
500 = 0 + 1/2 x 10 x t12
t12 = 100
t1 = 10s
time taken by the stone to reach the surface of water = 10 seconds
Case-I, Again, s = 500 m, v = 340 ms–1
from s = vt2
t2 s/v = 500/340
= 1.47s
time taken to hear the sound at the top.
t = t1 + t2
t = 10 + 1.47
t = 11.47s
Please verify your Whatsapp number first,
so you can download this pdf immediately
Send OTP
.svg){kind=logo}
